$\log_{0.25}\left(16\right)$
$\lim_{x\to0}\left(\left(2x^{3x}\right)\right)$
$\left(4x+16\right)^2$
$\int_{-3}^{-2}\left(\frac{1}{x}\right)dx$
$\int\left(\frac{1}{\sqrt{8x+5}}\right)dx$
$\:\frac{tan^2\theta\:}{sec^2\theta\:\:}$
$\frac{15m^5}{5m^2}$
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