$x^2=1+\sqrt{2}x$
$\frac{x-1}{2x-4}+\frac{x+2}{3x}=1$
$3x+9>3$
$sin=\frac{2}{3}$
$\frac{dy}{dx}+x=0$
$\frac{x^2}{\sqrt{x^2-1}}-x$
$\frac{dy}{dx}=\left(x^2+2x+1\right)$
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