$x^2+8x-1=0$
$\frac{4x\cdot4x+5}{2}$
$\int \frac { x } { ( x + 1 ) ( x ^ { 2 } + 1 ) } d x$
$\int_1^x\left(xu\right)du$
$\int\frac{1}{\left(4x^{2}-1\right)\left(x+7\right)}dx$
$\frac{dy}{dx}=\frac{\left(3x+2y\right)}{x}$
$2\left(x+y\right);\:x=\:1$
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