$\int\left(4x\right)\left(9+2x^2\right)^4dx$
$\frac{\left(9x^4-9x^3+12x^2-4x\right)}{\left(x+2\right)}$
$434+\frac{71}{4}-3.428-\frac{125}{10}-356+18.36$
$4x^{-2}\cdot2x^3$
$-12^1$
$2\left(5f+10g-9\right)$
$\left\{63-\left(52+19\right)\right\}-\:\left(14-\left(139\right)\right)$
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