$\frac{78.98}{11}$
$5-\left|3-\left(1-8\right)-3+6\right|+5$
$\frac{1+\tan\:^2\left(30\right)}{\sec^2\left(30\right)}=1$
$x^2+x+18$
$245x^4-45$
$\frac{1}{4}t-\frac{1}{2}=\frac{1}{8}t$
$\lim_{x\to4}\left(\frac{x-4}{\sqrt{-2}}\right)$
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