$\int\frac{1}{x\sqrt{100x^2+16}}dx$
$\int_4^{\infty\:}xe^{4-x}dx$
$\sqrt[6]{\left(x-1\right)\left(x+1\right)\left(x^2+1\right)\left(x^4+1\right)+1};\:x=36$
$12b^6+6^3-18^2$
$\frac{\:x^2+1}{x+1}$
$\left(5m^2+11n^4\right)^2$
$\int x\left(2x+5\right)^7dx$
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