$\frac{3x^2-x-2}{3x+2}$
$\frac{1}{x^2}=\frac{1}{x}-\frac{1}{2}$
$\left(6x^3-x\right)\left(10-20x\right)$
$\int\frac{x+7}{x^3-8x}dx$
$y''-9y=0$
$9x^2-24x+25$
$x^2-4x=18$
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