$\lim_{x\to\infty}\left(\frac{\left(2x-1\right)\left(2+3x\right)}{2x^2-5}\right)$
$2\left(n-1\right)+4n=2\left(3n-1\right)$
$\left(m^2-mn\right)+m$
$\frac{6c^8}{3c^{-3}}$
$x^{2}-7x-1$
$\frac{-12+\sqrt{-18}}{60}$
$7a\:+\:7b\:-\:7c\:-\:7$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!