$\frac{dy}{dx}=\sqrt{39}si\:\sqrt{36}=6$
$x^2\frac{dw}{dx}=\sqrt{w}\left(6x+1\right)$
$6\cdot3\cdot2\cdot1$
$\frac{-x^2-2x+1}{x+1}$
$-\frac{34}{34}$
$\frac{x}{3}>1$
$\left(a-5\right)\left(a^2-5a+25\right)$
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