$\frac{sin^2x-cos^2x}{1-tan^2x}$
$\lim_{x\to0}\left(\frac{-3\sin\left(7x\right)}{-4x^8}\right)$
$3cos^2\left(x\right)-7cos\left(x\right)+2$
$2xy^2z-xy+2;x=2;y=-2;z=-1$
$\left(9x^5\:+\:3\right)^2$
$.58+.22-1.25$
$\frac{x}{55}=0.\left(a+1\right)\left(a+2\right)$
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