$\frac{x+1}{x-2}<3$

$y^2-12y+1$

$6x-12+\frac{1}{4}x^2-7x+8$

$\left(\frac{2\left(\frac{3x}{x+1}\right)^3+4}{\left(\frac{3x}{x+1}\right)^2+2}\right)^6$

$\lim_{x\to0}\left(\frac{arcsin\left(x\right)-e^x+1}{4x^2+2x^3}\right)$

$\left(x+0.5\right)\left(x-0.8\right)$

$-2\left(x-6\right)+10$