$\lim_{x\to\infty}\left(\frac{\left(2x+1\right)^2}{2x^2+3x+1}\right)$
$\lim_{x\to1}\left(\frac{6^x-6}{x^2-1}\right)$
$x^2-4=52$
$\frac{dy}{dx}-y=\left(9x+7\right)\cdot e^x$
$\frac{\frac{x}{y}}{a}$
$\cos ydx+\sec^2xdy$
$\left(x-5\right)^2=81$
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