$3\:\:\left(1-x\right)<6$
$4x^2-40x+y+47=0$
$-18\cdot13$
$\frac{10}{0}+\frac{0}{12}$
$\sqrt{11a^3b}$
$\lim_{x\to\infty}\left(1+\frac{8}{x}\right)^{\frac{x}{6}}$
$\left(3x^2\right)\left(-\frac{2}{3x^3}\right)\left(4x^2\right)$
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