$\frac { 2 x ^ { 4 } - 5 x ^ { 3 } + 3 } { 2 x ^ { 2 } - 2 x }$
$7+4+5+8+1+2$
$\left(x^2\right)\:y'\:=\:2y^2$
$\lim_{x\to\infty}\frac{1-\left(4x^2+2x\right)}{x^2+4}$
$\left(3-5q\right)\left(3+5q\right)$
$a^4-5a^2+4$
$y=\frac{x^2\left(x^3+1\right)^4}{e^x\left(x+1\right)^5}$
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