$\lim_{x\to-4}\left(\frac{x^2-4x^3+4x^2}{x-2}\right)$
$8.3066-4.5826$
$\left(x^{2}+\sqrt{3}\right)\cdot\left(x^{2}-\sqrt{3}\right)$
$y\cdot z=\ln\left(x+z\right)$
$8x^3+64$
$-2\left(3\right)+5\left(-1\right)+3-2\left(-2\right)+2$
$\frac{7x+2x^2-6}{2x-3x^2}$
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