$\int\frac{3}{2x^2-3x}dx$
$\left(-3x^4y^6\right)^3$
$2x^2+18x-3=0$
$\frac{dy}{dx}=\left(x^2+1\right)$
$5^{2\:}\cdot3^2\cdot2^2$
$4720.3\cdot4.5$
$x+1>10$
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