$\left(3x^2\right).\left(\frac{1}{2}x\right).\left(-xy\right)$
$\left(2-3x\right)\left(1+x\right)\left(x+2\right)$
$x^2-8x+13=0$
$\sqrt[5]{192a^5b^{17}}$
$3x<9x+4$
$x^2-x-182$
$\frac{2xyz^3}{2x^2zy}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!