$\lim_{x\to\infty}\left(\ln\left(x\right)-\ln\left(x+1\right)\right)$

$\lim_{x\to0}\left(\frac{tan\left(2x\right)sec\left(3x\right)}{x}\right)$

$\frac{dy}{dx}=x^2\cos\left(y\right)$

$4\left(a-5\right)^2$

$\frac{15x}{3x}$

$-\left(3h+z\right)-\left[h-\left(z+2h\right)\right]\:$

$\left(sec\left(x\right)\right)\frac{dy}{dx}=e^{y+sin\left(x\right)}$