$3a^3+6m^3$
$1+\left(x-y+6\right)\frac{dy}{dx}=0$
$3tan4x=4$
$\left(-\frac{12x^{-3}}{6y^{-8}}\right)^{-1}$
$-24\:\cdot\:-7\:+\:67\:\cdot\:0$
$2xydx+2xdy=0$
$\frac{1}{x^2}=\frac{0.111}{1}$
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