$\left(5\right)\left(4\right)\left(-3\right)\left(-1\right)$
$6x^2-x-2=0$
$\left(\frac{1}{2}a^2-3b\right)^2$
$\frac{du}{dt}=e^{2u+9t}\:\:u\left(0\right)=7$
$cos2a+6cos^2a=1$
$\left(8fg-9\right)^2$
$4\left(6x-3-4y\right)$
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