$\lim_{x\to\infty}\:\frac{0^{x+1}}{1+0^x}$
$1-x\le3$
$2xydx+x^2-1dy=0$
$-3-2-8-7-20-15-9$
$10^5\:.1000:0'001$
$\lim\:_{x\to\:\pi\:}\left(\frac{3\left(1+\cos\:\left(x\right)\right)}{\left(x-\pi\:\right)\left(\tan\:\left(x-\pi\:\right)\right)}\right)$
$2-\left(-1\right)-\left(-2\right)$
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