$\left(4a^2\:+\:5\right)\:x\:\left(4a^2\:-\:2\right)$
$-3^2\left(6+4\right)$
$\left(2a^4-4a^2\right)^3$
$\lim_{x\to1}ln\left(\frac{3x^3-1}{\cos\left(x-1\right)}\right)$
$12^2-4$
$\left(18+32\right)\left(20-100\right)$
$\frac{3+x}{3-x}>1$
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