$\left(4i\right)\left(7+4i\right)$
$1\:\:0\:\:\:-12\:\:\:\:\:\:\:16\:$
$\frac{dy}{dx}=3ycos\left(x\right)-2cos\left(x\right)$
$\left(7+x^4\right)^2$
$\left(2xy\right)dy-\left(x^2+y^2\right)dx=0$
$\frac{b}{6}=3$
$t^2+7t$
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