$\lim_{x\to1}\left(\frac{x^3+x^2-5x+3}{x^3+2x^2-5x+4}\right)$
$-1\left(x+1\right)\left(x+6\right)$
$ln\left(x^3\sqrt{5-x}\right)$
$\frac{dy}{dx}+\frac{1}{20}y=0.75$
$2.5\:+0.5y\:-6+\:3.5y$
$\sec^2a\cdot\left(\csc^2a-1\right)=\csc^2a$
$x+4+\left(x-1\right)+3+2x$
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