$\left(3x+4\right)\left(x+4\right)$
$4r^2+5=r$
$\left(n^{-4}\right)^{-5}\cdot\left(n^{3}\right)^{4}$
$6xy+2xy^2+8xy^2$
$2x^2+8x-12=0$
$\frac{d}{dx}x^2+y^2=-1$
$4x^2-96x-576$
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