$\lim_{x\to1}\frac{x^4-1}{x-1}$
$y'-2x=2xy^2$
$2x+1<7$
$x^2+x\:=\:42$
$\:4x^2-4xy+y^2=0$
$y'-2x^3y^2=2x^3$
$cos3x\cdot cos2x-\frac{3}{2}\cdot cos2x+8\cdot cos3x$
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