$4\left(1\right)+4\left(9x\right)$
$\frac{\left(40-40e^{-\frac{1}{40}t}\right)}{400}$
$-5\left(x+4\right)$
$3-0.2$
$m^2n^3-2n;m=-5yn=-3$
$\int\:\frac{-7x}{x^2-11x+24}dx$
$4=\frac{w+11}{2}$
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