$\ln x=5$
$y'=y^2$
$13y^{-1}$
$\int\frac{7x^2}{\left(4x^3+5\right)}dx$
$4x-3x+5$
$y'=\frac{\left(3x+2y\right)}{-2x}$
$\int\left(\frac{x^2+6x+5}{x^2}\right)dx$
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