$6a^{-3}b^4$
$sin^2\left(x\right)\:\frac{sin\left(x\right)cos\left(x\right)}{tan\left(x\right)}$
$\int\left(6x+1\right)^4dx$
$1+\tan^2x=\sin^2$
$\frac{2xy}{4y}$
$\int\frac{3x}{x-1\left(x+2\right)}dx$
$3^{2m-1}=343^4$
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