$64y^6-48p^3y^3z^2+9p^6z^4$
$\int\frac{\sqrt{x^2+25}}{x^3}dx$
$\int ln\left(x+3\right)dx$
$y^2+28y$
$-\left[\left(+4\right)-\left(-3\right)-\left(+6\right)+\left(-4\right)\right]$
$\lim_{x\to\infty}\left(1+\frac{2}{x}\right)^{4x}$
$y'\:=\:\frac{2}{3}x\sqrt{1-9y^2}$
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