$3x^2\:+\:2x\:-\:8\:+9\:-\:x^2\:+\:8x$
$\frac{x}{y}=2,4$
$\int_1^4\left(\frac{2x^2-10x+4}{\left(x-5\right)^3}\right)dx$
$2\cdot9-7$
$x^2+x-72\ge0$
$_{\left(sec^2-1\right)^2}$
$1+cos2x+2sin^2x=2$
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