$\frac{\cos^2x-tan^2x}{sin^2x}$
$\left(3w-u\right)^3$
$7.4 z - 5 ( - 1.6 z + 2.4 )$
$x^3y^2=6$
$-\int\left(\frac{u^2-2u+5}{\left(u-2\right)\left(u+2\right)\left(u-1\right)}\right)du$
$\left(m+n-d\right)\left(m-d-n\right)$
$\sqrt{x}3\sqrt{x}+1$
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