$\left(x^2-y^3\right)\left(x^4-x^2y^3+y^6\right)$
$\frac{x^3-5x^2+7}{x-5}$
$6x^2+2x+10$
$\frac{\left(7x-13\right)}{\left(x^2-15x+54\right)}$
$3x^2y+15xy$
$3x^2+16=0$
$\left(10ab\:+\:15ac\:-\:25bc\:+\:5\right)\:+\:\left(4ab\:-\:8bc\:-\:12\right)$
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