$10x+6\ge x+3$
$91,36-15$
$\int\left(x^3\left(4+x^4\right)^8\right)dx$
$\frac{dy}{dt}=\left(9t^2\right)$
$\lim_{x\to0}\pi^3$
$\int\sqrt{1+\sin^2\left(x\right)}\cos\left(x\right)dx$
$\frac{81a^6-100b^8}{9^3+10b^4}$
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