$\left(2x^2+3x-2\right)^2$
$\frac{4-2y}{3}>\frac{2y-3}{3}$
$\frac{12\left(x-2\right)^2}{6\left(x-2\right)\left(x+5\right)}$
$3^1\cdot3^0$
$\left(\frac{2a^3}{5}-6\right)^2$
$\frac{\left(-2xy^2\right)\left(5x^{2y}\right)}{\left(5y^2\right)\left(-4x^5\right)}$
$x^2+4x-1=0$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!