$2\sin\left(x\right)\cos\left(x\right)=-\sqrt{3}\sin^2\left(x\right)$
$\int\frac{\sec^2x}{\sqrt{1-\tan^2x}}dx$
$\frac{dy}{dx}=\frac{2y}{3y^2}$
$\frac{1-\sin x}{1+\sin x}$
$8\cdot9+2$
$6x^4-3x^3+2x^2$
$\int\left(\frac{\left(2x-8\right)}{\left(x^2-8x+15\right)^4}\right)dx$
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