$\frac{dy}{dx}=\left(3x+2\right)^2$

$\frac{dy}{dx}=\frac{\left(1+x\right)}{y^9x}$

$\left(2x-x\right)\cdot\left(3x^2+6x\right)$

$x=-x+\sqrt{x^2-4\left(x\right)\left(-5\right)}$

$y-\frac{1}{3}\ge8$

$\int\frac{x^2+4}{x\left(x^2+1\right)\left(x-1\right)}dx$

$2\frac{dy}{dx}=\sin\left(2x\right)$