$\int\frac{x}{\left(4x^2+9\right)^2}dx$
$\left(9x-3xt\right)^3$
$\frac{6x^2+19x+12}{x+2}$
$45,61\:-\:7,326\:$
$1-\sin^2\left(a\right)\cdot1+\tan^2\left(a\right)=1$
$\frac{dy}{dx}=\sqrt{y^2-4}$
$-\left(x+10\right)\left(x-15\right)$
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