$\frac{dy}{dx}=\sqrt{y}\sin\left(2x\right)$
$-2x\left(4x^2+1\right)$
$dx-e^{-3x}dy=0$
$\frac{44}{11}m^{3}$
$4^{-2}\cdot4^4$
$-2x+5>x+3$
$\lim_{x\to0}\left(\frac{\sin^3\left(x\right)}{x^2.\tan\left(3x\right)}\right)$
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