$\frac{16}{8}$
$2x-7\ge5$
$\frac{x}{-2}+17=12$
$\log\left(9-x\right)=\log\left(2x-6\right)$
$\left(\frac{1}{2}x^3\right)\left(-18x\right)$
$-2-\left(-7\right)+5-\left(+2\right)+\left(+7\right)$
$\frac{\sec^2x\csc x}{\sec^2x+\csc^2x}$
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