$\left(x\:-\:4\right)\:\left(x^3\:-\:5\:x^2\:-\:12\:x\:-\:1\right)\:$
$7x^2+9x-130$
$\frac{3x^2-2x^2+x-3}{3x+2}$
$\frac{2\cdot6}{3}\cdot\frac{6\cdot6}{4}$
$4x+1<13$
$\:\left(4x-6\right)^2$
$\csc x^2-\csc x=0$
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