$\int\sin^2\left(x\right)x\cdot\cos^2\left(x\right)dx$

$\sqrt{11arctan\left(x\right)}$

$-10=3x-x^2$

$\left(-5x+3\left(\frac{x}{6}-\frac{1}{3}\right)\right)\left(x-\left(2x-1\right)\right)+4x-3x^2$

$\left(\left(x^2+7xy\right)\left(\:3x^3-2y\right)\right)-3\left(2x^3+6x^4y\right)$

$\left(y-3\right)\left(y+9\right)$

$\frac{4x+3}{3}-x=\frac{5}{6}x$