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# Find the discriminant of the equation $-x^2+7x-10=0$

## Step-by-step Solution

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sinh
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asinh
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asech
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###  Solution

$9$
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##  Step-by-step Solution 

Problem to solve:

$-x^2+7x-10=0$

Specify the solving method

1

The discriminant (D) of a quadratic polynomial of the form $ax^2+bx+c$ is calculated using the following formula, where $a$, $b$ and $c$ are the coefficients of the corresponding terms

$D=b^2-4ac$
2

From the equation, we see that $a=-1$, $b=7$ and $c=-10$. Replacing the values of $a$, $b$ and $c$ in the previous formula, we obtain

$D=7^2-1\cdot 4\cdot -1\cdot 1\cdot -10$
3

Multiply $-1$ times $4$

$7^2-4\cdot -1\cdot 1\cdot -10$
4

Multiply $-4$ times $-1$

$7^2+4\cdot 1\cdot -10$
5

Multiply $4$ times $1$

$7^2+4\cdot -10$
6

Multiply $4$ times $-10$

$7^2-40$
7

Calculate the power $7^2$

$49-40$
8

Subtract the values $49$ and $-40$

$9$
9

The discriminant of the polynomial results in

$9$

$9$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SimplifyFactorFactor by completing the squareFind the integralFind the derivativeFind -1x^2+7x=0 using the definitionFind the rootsFind break even points

SnapXam A2

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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