$\left(4a-3b^2\right)\left(4a+3b^2\right)$
$\int_0^1t\cos\left(ht\right)\:dt$
$\left(-2\right)-\left(-4+2\right)+\left(-1\right)$
$1^{10}-1^5\cdot\sqrt{4-25+7\cdot2}$
$\cos\left(y\right)\sec\left(y\right)-\cos\left(y\right)=\sin^2\left(y\right)$
$\frac{3a^{3x}+9b^{3y}}{3b^y+\sqrt[3]{3a^{2x}}}$
$-6m+8n-5-m-n-6m-11$
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