$\lim_{x\to0}\left(6x^3-6x\right)$

$\lim_{x\to\infty}\left(\frac{8x^2+3x+2}{\sqrt[2]{2x^4+x^3}}\right)$

$\left(1+\sin\:\left(\alpha\:\right)\right)^'\left(1-\sin\:\left(\alpha\:\right)\right)^'=\frac{1}{\sec\:^2\left(\alpha\:\right)}$

$\frac{5x^2y^3-35x^5y^4}{5x^5y^4}$

$-x^2-5x+4$

$\left(5^3\right)^6$

$\left(8+c\right)^2$