$3-4x=19$
$\lim_{x\to-1}\left(\frac{\sqrt{x}-3}{9-x}\right)$
$-4\cdot140$
$9x^2-42x+49=0$
$\cos\left(x\right)\left(\frac{1+\tan^2\left(x\right)}{\sec^2\left(x\right)}\right)$
$\frac{1-\cos\left(2u\right)}{2}$
$8.322-2$
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