$\frac{dx}{dt}=x+t$
$\int e^{7x}dx$
$-6\left(3x-8\right)=b-18$
$2x\:dx\:=\:y\:dy$
$a^4-a^2b^2+\frac{64}{4}$
$64-b^{12}$
$a^2-8\cdot a^2-9$
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