$\int\:\frac{x+2}{x^2-5x+6}dx$
$\left(3y-5z\right)\left(6y-9z\right)$
$\frac{\left(7x-3\right)^2}{x-1}$
$y=\frac{\left(e^x\cdot\left(x+3\right)^3\right)}{x\cdot\left(x+1\right)\cdot\left(x+2\right)^2}$
$2x^2-x-10=0$
$\left(7^{15}\right)^2$
$y'+3x^2+y=x^2$
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