$y=\ln\left(8-4x^2\right)$
$\left(1+x^2\right)y'=\arctan\:\left(x\right)$
$n2\:\:-\:17n\:-\:60$
$\left|-11\right|-\left|-6\right|$
$2.54-4.12$
$16-4a^2$
$\int\left(\frac{1}{2x+6}\right)dx$
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