$4x-16\::\:x\:-\:1$
$\sqrt[4]{5^2}$
$\int\left(\left(\frac{16x^3}{x^4+7}\right)\right)dx$
$sec2\:x\:-\:csc2\:x\:$
$\frac{dy}{dx}=y\left(5-y\right)$
$\frac{x^6}{x^4}$
$9x^2-40x+25$
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